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in triangles abc,de parallel to bc, if bd=x-3,ab=2x,ce=x-2 and ac=2x+3.find x
Please find the answer to your question below Since DE is parllel to BC,by basic proportionality theorem(AB/DB)=(AC/EC)(2x/x-3)=(2x+3/x-2)By cross multiplication we get ,2 x^2 - 4x = 2 x^2 - 3x -9x = 9Hope it helps
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