0

Guest

Courses New

in triangles abc,de parallel to bc, if bd=x-3,ab=2x,ce=x-2 and ac=2x+3.find x

in triangles abc,de parallel to bc, if bd=x-3,ab=2x,ce=x-2 and ac=2x+3.find x

Grade:10

1 Answers

Arun
25757 Points
5 years ago
Please find the answer to your question below Since DE is parllel to BC,by basic proportionality theorem(AB/DB)=(AC/EC)(2x/x-3)=(2x+3/x-2)By cross multiplication we get ,
2 x^2 - 4x = 2 x^2 - 3x -9
x = 9
Hope it helps

Think You Can Provide A Better Answer ?

Other Related Questions on 10 grade maths

View all Questions »

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More