Flag 10 grade maths> In triangle abc DE parallel to BC and CD ...
question mark

In triangle abc DE parallel to BC and CD parallel to EF P.T (Ad)2 =AE ×AB

Keerthi aradhya , 6 Years ago
Grade 10
anser 1 Answers
Arun

Last Activity: 6 Years ago

In ΔABC,  we have  CD/DA = CE/EB      as AB || DE
in ΔCDB,  we have  CF/FD = CE/EB     as  EF || BD
hence we get   CD/DA = CF/FD
=> Reciprocals:     DA/CD = FD /CF
=> Add 1 on both sides:     AC /CD = DC/CF
=>    DC^2 = CF * AC
You can similarly prove relations like this.
Hope it helps
Actually I have answered it before so I have directly put this
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments