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In triangle ABC, bisectors of angle B and angle C meet each other at point P. Line AP when extended, cuts the side BC at Q. Then AP by AQ is equal to 1)AB+AC by BC. 2)BC+AC by AB. 3)AB+BC by AC. 4)AB by AC.

In triangle ABC, bisectors of angle B and angle C meet each other at point P. Line AP when extended, cuts the side BC at Q. Then AP by AQ is equal to 1)AB+AC by BC. 2)BC+AC by AB. 3)AB+BC by AC. 4)AB by AC.

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Grade:10

1 Answers

Utkal
29 Points
5 years ago
In triangle ABQ we can se that triangle ABQ is similar with triangle ABQ therefore AB/PB=AQ/PQ =AP/PQ AND IF WE CRISS MULTUPLY WE VAN GET THAT AP/PQ =AB÷AC

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