In triangle ABC , b=90degree BD Perpendicular to AC area of triangle ABC=A and BC=a then prove that BD=2Aa/root 4A^2 + a^4`

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Nishant Vora · Answer

Dileep Rajpoot · Answer

In ∆ABC angle B=90° ,BD,perpendicular AC ,area of (∆ABC)=A ,and BC =a .than prove that BD=2Aa÷√4A²+a⁴.

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In triangle ABC , b=90degree BD Perpendicular to AC area of triangle ABC=A and BC=a then prove that BD=2Aa/root 4A^2 + a^4`

In triangle ABC , b=90degree BD Perpendicular to AC area of triangle ABC=A and BC=a then prove that BD=2Aa/root 4A^2 + a^4`

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In triangle ABC , b=90degree BD Perpendicular to AC area of triangle ABC=A and BC=a then prove that BD=2Aa/root 4A^2 + a^4`

In triangle ABC , b=90degree BD Perpendicular to AC area of triangle ABC=A and BC=a then prove that BD=2Aa/root 4A^2 + a^4`

2 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on 10 grade maths

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