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Grade 1110 grade maths

IN ANY TRIANGLE ABC, THERE’S A POINT P IN THE INTERIOR OF THE TRIANGLE. IT IS GIVEN THAT : AP^2 = BP^2 + CP^2. PROVE THAT ANGLE BPC = 150 DEGREE.

Profile image of Sumit Bhattacharya
11 Years agoGrade 11
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1 Answer

Profile image of Sourabh Singh
10 Years ago
Hii
Use trigonometry in order to get the relation.. As triangle is not mentioned and not the postion of point also.Use it anywhere in between the triangular area.