MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 10
        
In an acute angled triangle,if sin(A+B-C)= 1/2 and cos(B+C-A)= 1/√2, find A,B and C
one year ago

Answers : (2)

Deepak Kumar Shringi
askIITians Faculty
4398 Points
							sin 30=1/2 and cos45= 1/root2
A+B-C=30
B+C-A=45
A+B+C=180
B=75/2
C=75
A=67.5
one year ago
Ramnath Venkatesh
31 Points
							
It is given that sin (A+B-C)=1/2 and cos(B+C-A)=1/(root)2
But, sin 30=1/2 and cos 45= 1/(root)2
=>A+B-C=30------(1)
and 
    B+C-A=45-------(2)
from (1) and (2),
A=135/2
B=75/2
C=75
 
 
one year ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 728 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details