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In an acute angled triangle,if sin(A+B-C)= 1/2 and cos(B+C-A)= 1/√2, find A,B and C
sin 30=1/2 and cos45= 1/root2A+B-C=30B+C-A=45A+B+C=180B=75/2C=75A=67.5
It is given that sin (A+B-C)=1/2 and cos(B+C-A)=1/(root)2But, sin 30=1/2 and cos 45= 1/(root)2=>A+B-C=30------(1)and B+C-A=45-------(2)from (1) and (2),A=135/2B=75/2C=75
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