In an acute angled triangle,if sin(A+B-C)= 1/2 and cos(B+C-A)= 1/√2, find A,B and C

Question

Deepak Kumar Shringi · Answer

sin 30=1/2 and cos45= 1/root2 A+B-C=30 B+C-A=45 A+B+C=180 B=75/2 C=75 A=67.5

Ramnath Venkatesh · Answer

It is given that sin (A+B-C)=1/2 and cos(B+C-A)=1/(root)2 But, sin 30=1/2 and cos 45= 1/(root)2 =>A+B-C=30------(1) and B+C-A=45-------(2) from (1) and (2), A=135/2 B=75/2 C=75

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In an acute angled triangle,if sin(A+B-C)= 1/2 and cos(B+C-A)= 1/√2, find A,B and C

In an acute angled triangle,if sin(A+B-C)= 1/2 and cos(B+C-A)= 1/√2, find A,B and C

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