Anand Chauhan
Last Activity: 6 Years ago
x2-5x+1=0
x2+1=5x
now on dividing both side by x we get
x+ 1/x = 5
now squaring both sides
x2+ 1/x2+2=25
x2+ 1/x2=23 let this be equation number 1
Now multiply it by x+ 1/x
(x2+1/x2)(x+ 1/x)= (23)(5) ---------(since x+ 1/x = 5 (see third step ))
x3 + 1/x3 + (x+ 1/x) = 115
x3 + 1/x3 = 110 ---------(since x+ 1/x = 5 (see third step )) (Now let this be equation number 2)
now multiply equation number 1 and 2
(x2+ 1/x2)(x3 + 1/x3) = (23)(110)
x5+1/x5+ (x+ 1/x) = 2530
x5+1/x5=2530-5
x5+1/x5=2525