If (x+y)1/3+(y+z)1/3+(z+x)1/3=0 thenshow that (x+y+z)3=9(x3+y3+z3)
If (x+y)1/3+(y+z)1/3+(z+x)1/3=0 then
show that (x+y+z)3=9(x3+y3+z3)
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