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If X greater than 0 and Y greater than 0 and X+Y=18 then the minimum value of XY is A. -1 B. 1 C. 2 D. -2
Dear student Let A = xyA = x (18-x) dA/dx = 18 -2x = 0x = 9 Now d²A /dx² = -2 (maximum) Hence maximum of A will exist when x = y = 9 Hence A = xy = 9*9 = 81
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