If the sum of the circumferences of two circles with radii Rj and R2 is equal to the circumference of a circle of radius R, then [NCERT Exemplar Problems]
(a) R1 + R2 = R
(b) R1 + R2 > R
(C) R1 + R2 < R
(d) nothing definite can be said about the relation among Rp1, R2 and R.

Question

If the sum of the circumferences of two circles with radii Rj and R2 is equal to the circumference of a circle of radius R, then [NCERT Exemplar Problems] (a) R1 + R2 = R (b) R1 + R2 > R (C) R1 + R2

Pawan Prajapati · Answer

Answer: a Explaination: (a) 2πR1 + 2πR2 = 2πR ⇒ R1 + R2 = R.

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If the sum of the circumferences of two circles with radii Rj and R2 is equal to the circumference of a circle of radius R, then [NCERT Exemplar Problems] (a) R1 + R2 = R (b) R1 + R2 > R (C) R1 + R2 (d) nothing definite can be said about the relation among Rp1, R2 and R.

If the sum of the circumferences of two circles with radii Rj and R2 is equal to the circumference of a circle of radius R, then [NCERT Exemplar Problems]
(a) R1 + R2 = R
(b) R1 + R2 > R
(C) R1 + R2 < R
(d) nothing definite can be said about the relation among Rp1, R2 and R.

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If the sum of the circumferences of two circles with radii Rj and R2 is equal to the circumference of a circle of radius R, then [NCERT Exemplar Problems] (a) R1 + R2 = R (b) R1 + R2 > R (C) R1 + R2 (d) nothing definite can be said about the relation among Rp1, R2 and R.

If the sum of the circumferences of two circles with radii Rj and R2 is equal to the circumference of a circle of radius R, then [NCERT Exemplar Problems] (a) R1 + R2 = R (b) R1 + R2 > R (C) R1 + R2 < R (d) nothing definite can be said about the relation among Rp1, R2 and R.

1 Answers

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If the sum of the circumferences of two circles with radii Rj and R2 is equal to the circumference of a circle of radius R, then [NCERT Exemplar Problems]
(a) R1 + R2 = R
(b) R1 + R2 > R
(C) R1 + R2 < R
(d) nothing definite can be said about the relation among Rp1, R2 and R.