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If the line x/a + y/b =1 passes through the point of intersection of the line x=3 and 2x+3y=12 and is perpendicular to the line 2x+3y=8, Find the value of a and b.

If the line x/a + y/b =1 passes through the point of intersection of the line x=3 and 2x+3y=12 and is perpendicular to the line 2x+3y=8, Find the value of a and b.

Grade:10

1 Answers

Arun
25763 Points
4 years ago
when x/a + y/b =1
 
is written in simplified form
bx + ay = ab
hence slope  = –b/ a
 
now line passes through (3, 2)               (intersection of two lines)
3 b  + 2a = ab
 
now if two lines are perpendicular then product of slope will be  – 1
hence
 (– 2/ 3)* ( –b/ a) = – 1
2b = – 3a
now use the above equation in the another relation of a & b
 
you will get the answer.
 
Hope it helps

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