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if the each alggebric expression lx^2+mx+n, mx^2+nx+l and nx^2+lx+m are perfect squares then what is (l+m)/n sir is the answer to this is 2
all the expression have D = 0 hence x = – m / 2l …....(i) x = – n / 2m ….....(ii) x = – l / 2n ….........(iii) from eqn (i) m = – 2lx pu this in (ii) n = 4lx^2 hence x = – ½ if you put this in (i) and (ii) you get l = m = n hence l + m / n = m + m / m = 2 m / m = 2 hope it helps
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