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Grade 1010 grade maths

If the difference between the roots of equation x^2+ax+1=0is less than √5,then the set of possible value of a is:

Profile image of Anubhuti
9 Years agoGrade 10
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1 Answer

Profile image of Saswat Pani
8 Years ago
x^2+ax+1=01ts root (-a + √a^2-4)/2 - (-a - √a^2-4)/2