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If the difference between the roots of equation x^2+ax+1=0is less than √5,then the set of possible value of a is:

Anubhuti , 7 Years ago
Grade 10
anser 1 Answers
Saswat Pani

Last Activity: 7 Years ago

x^2+ax+1=01ts root (-a + √a^2-4)/2 - (-a - √a^2-4)/2

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