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Grade 910 grade maths

If the difference between the ages of two persons is 8. 15 years ago the age of the elder one was twice the age of the younger one. find their present ages ( with steps please)

Profile image of sudarsan R
8 Years agoGrade 9
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4 Answers

Profile image of Arun
8 Years ago
Dear student
 
Let the age = x and y where x>y
 
Now
x -y = 8
 
x -15 = 3(y -15)
x -15 = 3y - 45
x -3y = -30
 
Now solve the equations
2y = 38
Hence y = 19 years and x = 27 years
Profile image of sudarsan R
8 Years ago
Let the eldder age be x and younger age be y.X-y=8.........…........................./(1)X-15=2y-30,.....................................(2)X=41Y=23
Profile image of Arun
ApprovedApproved Tutor Answer8 Years ago
Sorry I got wrong. Actually I read tgrice in stead of twice by mistake. Sorry. Hope you understand. Regards....arun
Profile image of nitya prakash gupta
8 Years ago
Let,
Firstperson age=x years,2nd person age=y years
And x>y,
ATQ:-
x-y=8
So x=8+y______(1)
Also,
x-15=2(y-15)_____(2)
Put x=8+y in (2),then,we have,
y+8-15=2y-30
=> y-7=2y-30
=>y=23
Now,x=8+y=31
 
So 1st person age=31years
      2nd person age=23 years