If tanA=ntanB and sinA = msinB, then prove that cos^2A= m^-1 / n^+1

Question

sonika p · Answer

sinA = msinB....(1) tanA= ntanB (sinA/cosA) = n(sinB/cosB)....(2) substuting sinB value from equation (1) cosB = (n/m) cosA......(3) sin 2 A = m 2 sin 2 B 1-cos 2 A = m 2 (1-cos 2 B) substituting equation (3) 1-cos 2 A = m 2 [1 – ((n 2 /m 2 )cos 2 A)] 1 – cos 2 A = m 2 – n 2 cos 2 A n 2 cos 2 A – cos 2 A = m 2 – 1 cos 2 A = (m 2 – 1)/(n 2 – 1)

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

If tanA=ntanB and sinA = msinB, then prove that cos^2A= m^-1 / n^+1

If tanA=ntanB and sinA = msinB, then prove that cos^2A= m^-1 / n^+1

1 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on 10 grade maths

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship