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If sinA+sinB=1/2 and cosA+cosB=1/4 then prove that tan(A+B)/2=0
sinA+sinB=1/2so, 2sin(A+B)/2* cos(A-B)/2=1/2cosA+cosB=1/4so, 2cos(A+B)/2*cos(A-B)/2=1/4Dividing both equations,We get,tan(A-B)/2=2
Sin A + sin B=1/2 Sin (A+B)=1/2 Cos A+ cos B =1/4 Cos (A+B)=1/4 Sin (A+B)/cos (A+B)=1/2×4/1=2 Sin (A+B)/cos (A+B)=tan(A+B)=2 Now dividing both sides by 2,we have Tan(A+B)/2=2/2 Tan(A+B)/2=1 Tan (A+B)=1
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