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If sin x +sin^2 x=1 then find the value of cos^8 x +2cos^6 x+cos^4 x (INDEX; ^2 : means to the power of)
Sinx +sin²x=1sinx=1-sin²xsinx=cos²xsin²x=cos⁴xso,cos^8x+2cos^6x+cos⁴x=cos⁴x(cos⁴x+2cos²x+1)=sin²x (sin²x+2sinx+1)=sin⁴x+2sin³x+sin²x=sin⁴x+sin³x+sin³x+sin²x=sin²x(sin²x+sinx)+ sinx(sin²x+sinx)=sin²x×(1)+ sinx(1)=sin²x+sinx= 1
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