If sin θ = √3/2, find the value of all T-ratios of θ.

Question

Harshit Singh · Answer

Dear Student Given function: sin &theta; = &radic;3/2 We know that sin𝜃= BC/AC = (Perpendicular)/Hypotenuse =&radic;3/2 By Pythagoras Theorem: AC^2 = AB^2 + BC^2 AB^2 = AC^2 - BC^2 = 4k^2&ndash;3k^2 = k^2 AB = k Find other T-ratios using their definitions: Cos 𝜃= AB/AC = 1/2 Tan𝜃= BC/𝐴𝐵= &radic;3 𝑐𝑜𝑠𝑒𝑐 𝜃= 1/sin𝜃= 2/&radic;3 sec𝜃= 1/cos𝜃= 2 cot𝜃= 1/tan𝜃= 1/&radic;3 Thanks

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If sin θ = √3/2, find the value of all T-ratios of θ.

If sin θ = √3/2, find the value of all T-ratios of θ.

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