If one root of tge equation x^2-px+q=0is m times the other root then m/(1+m)^2 is equal to

Question

Santhosh · Answer

ANS=q÷p^2. Take {alpha} and{ m×alpha} as two roots now alpha(1+m)=p,m×alpha^2=q Square first relation and divide with second amd we get final result

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If one root of tge equation x^2-px+q=0is m times the other root then m/(1+m)^2 is equal to

If one root of tge equation x^2-px+q=0is m times the other root then m/(1+m)^2 is equal to

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If one root of tge equation x^2-px+q=0is m times the other root then m/(1+m)^2 is equal to

If one root of tge equation x^2-px+q=0is m times the other root then m/(1+m)^2 is equal to

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Other Related Questions on 10 grade maths

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