If np(r-1)/a = npr/b = np(r-1)/c, show that b^2 = a(b+c)

Question

Arun · Answer

Dear suresh just assume every term = k Now solve this you can clearly prove this. Hope it helps Regards Arun

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If np(r-1)/a = npr/b = np(r-1)/c, show that b^2 = a(b+c)

If np(r-1)/a = npr/b = np(r-1)/c, show that b^2 = a(b+c)

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If np(r-1)/a = npr/b = np(r-1)/c, show that b^2 = a(b+c)

If np(r-1)/a = npr/b = np(r-1)/c, show that b^2 = a(b+c)

1 Answers

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