if M,N and T are in arithmetic progression prove that [M+2N-T][2N+T-M][T+M-N]=4MNT

Question

Santhosh · Answer

Put M=a, N=a+d T=a+2d and then by solving given lhs we get (2a)(2a+4d)(a+d) = 4a(a+d)(a+2d) =4MNT Provided the assumption is because given they are in AP If they are in GP use M=a÷r ,N=a,T=ar for else question

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if M,N and T are in arithmetic progression prove that [M+2N-T][2N+T-M][T+M-N]=4MNT

if M,N and T are in arithmetic progression prove that [M+2N-T][2N+T-M][T+M-N]=4MNT

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if M,N and T are in arithmetic progression prove that [M+2N-T][2N+T-M][T+M-N]=4MNT

if M,N and T are in arithmetic progression prove that [M+2N-T][2N+T-M][T+M-N]=4MNT

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