 ×     #### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
IF d IS H.C.F OF 56 AND 72 FIND x,y SATISFYING d=56x+72y. Also show that x and y are not unique

```
6 years ago

```							According to Euclid`s algorithm,
a=bq+r
so 72=56*1+16  ......(1)
56=16*3+8     .....(2)
16=8*2+0
H.C.F (56,72)= 8

Now 8=56-16*3   ......(2)
8=56- (72-56*1)*3   .....(1)
8=56- (72-56)*3
8=56-3(72-56)
8=56-72*3 +56*3
8=56(1+3) +72(-3)
8=56*4 +72(-3)
Taking x=4 and y=-3
8=56x+72y
Also x and y not equal to 1(Proved).
```
6 years ago
```							According to Euclid division Lemma72=56*1+1656=16*3+816=8*2+0.......  Therefore 8 is the HCF. Now,,,, 8=56-(16*3)..... In this step we have expressed 8 in form of 56 and 16,  we have to express it in the form of 56 and 72. So,            Now by splliting 16  we get,.       8=56-(72-56*1)(3)      8 =56-72*3+56*3.......   As we have another 56 we group them    8 =56*4+72(-3).  Hence X and Y are 4,3 respectively .. Therefore X and Y are not equal
```
2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on 10 grade maths

View all Questions »  ### Course Features

• 728 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions