Arun
Last Activity: 6 Years ago
Given cot theta +tan theta = m
1/tan theta+ tan theta = m.........(1)
sec theta - cos theta = n
sec theta - 1/ sec theta = n ........(2)
Using equation (1) and (2)
(m^2n)^(2/3)-(mn^2)^(2/3)
((1/tan theta+ tan theta)^2(sec theta - 1/ sec theta))^(2/3)-((1/tan theta+ tan theta)(sec theta - 1/ sec theta)^2)^(2/3)
(1/cos^6 theta)^(1/3)-(sin^6 theta/cos^6 theta)^(1/3)
sec^2 theta-tan^2 theta
=1