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`        If cot A+ tan A = m sec A – cos A = n , prove that:(m2n)2/3-(mn2)2/3 = 1.`
one year ago

```							Given cot theta +tan theta = m1/tan theta+ tan theta = m.........(1)sec theta - cos theta = nsec theta - 1/ sec theta = n ........(2)Using equation (1) and (2)(m^2n)^(2/3)-(mn^2)^(2/3)((1/tan theta+ tan theta)^2(sec theta - 1/ sec theta))^(2/3)-((1/tan theta+ tan theta)(sec theta - 1/ sec theta)^2)^(2/3)(1/cos^6 theta)^(1/3)-(sin^6 theta/cos^6 theta)^(1/3)sec^2 theta-tan^2 theta=1
```
one year ago
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