If cos (α + β) = 0, then sin (α – β) can be reduced to [NCERT Exemplar Problems]
(a) cos β
(b) cos 2β
(c) sin α
(d) sin 2α

Question

If cos (α + β) = 0, then sin (α – β) can be reduced to [NCERT Exemplar Problems] (a) cos β (b) cos 2β (c) sin α (d) sin 2α

Pawan Prajapati · Answer

Answer: b Explaination: (b) cos (α + β) = 0 = cos 90° ⇒ α + β = 90° sin (α – β) = sin (α – β + β – β) = sin (α + β – 2β) = sin (90° – 2β) = cos 2β

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If cos (α + β) = 0, then sin (α – β) can be reduced to [NCERT Exemplar Problems] (a) cos β (b) cos 2β (c) sin α (d) sin 2α

If cos (α + β) = 0, then sin (α – β) can be reduced to [NCERT Exemplar Problems]
(a) cos β
(b) cos 2β
(c) sin α
(d) sin 2α

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If cos (α + β) = 0, then sin (α – β) can be reduced to [NCERT Exemplar Problems] (a) cos β (b) cos 2β (c) sin α (d) sin 2α

If cos (α + β) = 0, then sin (α – β) can be reduced to [NCERT Exemplar Problems] (a) cos β (b) cos 2β (c) sin α (d) sin 2α

1 Answers

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If cos (α + β) = 0, then sin (α – β) can be reduced to [NCERT Exemplar Problems]
(a) cos β
(b) cos 2β
(c) sin α
(d) sin 2α