If alfa, beta are the zeroes of (x-l)(x-m)-n, prove that l,m are zeroes of (x-alpha)(x-beta)+n

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Arun · Answer

Dear student (x - alpha) (x - beta) = (x-l) (x-m) -n Now (x- alpha) (x- beta) +n = (x-l) (x-m) Hence l and m are roots

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If alfa, beta are the zeroes of (x-l)(x-m)-n, prove that l,m are zeroes of (x-alpha)(x-beta)+n

If alfa, beta are the zeroes of (x-l)(x-m)-n, prove that l,m are zeroes of (x-alpha)(x-beta)+n

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If alfa, beta are the zeroes of (x-l)(x-m)-n, prove that l,m are zeroes of (x-alpha)(x-beta)+n

If alfa, beta are the zeroes of (x-l)(x-m)-n, prove that l,m are zeroes of (x-alpha)(x-beta)+n

1 Answers

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Other Related Questions on 10 grade maths

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