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if a,b are solutions of x^2+2014x+1 and c,d are solutions of x^2-2015 x+1 find (a+c)(b+c)(a-b)(b-d)
Multiple (i mean open the brackets), so after that you will get terms of ab,ac,ca....all the non get able terms get cancelled and you will get ab,cd,(i hope a+b,c+d,..)so use alpha+beta=-b/a and alpha*beta=c/a.Hope u got it.[THE TERMS MIGHT MATCH BUT THE APPROCHE IS CORRECT]
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