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How many zeros does the polynomial (x – 3) 2 – 4 can have? Also, find its zeroes.

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one month ago Anand Kumar Pandey
1492 Points
```							Dear StudentGiven equation is (x – 3)^2– 4Now, expand this equation.=> x^2+ 9 – 6x – 4= x^2– 6x + 5As the equation has a degree of 2, the number of zeroes will be 2.Now, solve x^2– 6x + 5 = 0 to get the roots.So, x^2– x – 5x + 5 = 0=> x(x – 1) -5(x – 1) = 0=> (x – 1)(x – 5) = 0x = 1, x = 5So, the roots are 1 and 5.Thanks
```
one month ago
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