10 grade maths
How do you evaluate sin(−3pi)?
How do you evaluate sin(−3pi)?
1 Answer
Askiitians Tutor Team
To evaluate sin(−3π), we can use the periodicity property of the sine function.
The sine function has a period of 2π. This means that for any angle θ, sin(θ) = sin(θ + 2nπ), where n is an integer.
To simplify sin(−3π), we can add multiples of 2π to bring the angle within the range of 0 to 2π.
sin(−3π) = sin(−3π + 2π) = sin(−π)
Now, we know that sin(−π) = −sin(π), because sine is an odd function.
The value of sin(π) is 0. Therefore, sin(−π) = −0 = 0.
So, sin(−3π) = 0.
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