Grade 1210 grade maths
Given that HCF (306, 657) = 9, find LCM (306, 657).
Given that HCF (306, 657) = 9, find LCM (306, 657).
2 Answers
Harshit Singh
Dear Student
HCF ×LCM = Product of the two given numbers
Therefore
9×LCM = 306×657
LCM = (306×657)/9 = 22338
Hence, LCM(306,657) = 22338
Thanks
HCF ×LCM = Product of the two given numbers
Therefore
9×LCM = 306×657
LCM = (306×657)/9 = 22338
Hence, LCM(306,657) = 22338
Thanks
Ram Kushwah
Let a=306 and b=657
given HCF(306,657) = 9
We know that LCM x HCF = a x b
So LCM = (a x b) / HCF
=306 x 657 /9
=201042 / 9
=22338
Thus LCM( 306,657) =22338
Thanks
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