Given, ABC
is a triangle and PQ
is a straight line meeting AB
in P
and AC
in Q
. If AP=1 cm
, PB=3 cm
, AQ=1.5 cm
, QC=4.5 cm
, prove that the area of △APQ
is one-sixteenth of the area of △ABC
.

Question

Given, ABC is a triangle and PQ is a straight line meeting AB in P and AC in Q . If AP=1 cm , PB=3 cm , AQ=1.5 cm , QC=4.5 cm , prove that the area of △APQ is one-sixteenth of the area of △ABC .

Pawan Prajapati · Answer

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Given, ABC is a triangle and PQ is a straight line meeting AB in P and AC in Q . If AP=1 cm , PB=3 cm , AQ=1.5 cm , QC=4.5 cm , prove that the area of △APQ is one-sixteenth of the area of △ABC .

Given, ABC
is a triangle and PQ
is a straight line meeting AB
in P
and AC
in Q
. If AP=1 cm
, PB=3 cm
, AQ=1.5 cm
, QC=4.5 cm
, prove that the area of △APQ
is one-sixteenth of the area of △ABC
.

1 Answers

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Given, ABC is a triangle and PQ is a straight line meeting AB in P and AC in Q . If AP=1 cm , PB=3 cm , AQ=1.5 cm , QC=4.5 cm , prove that the area of △APQ is one-sixteenth of the area of △ABC .

Given, ABC is a triangle and PQ is a straight line meeting AB in P and AC in Q . If AP=1 cm , PB=3 cm , AQ=1.5 cm , QC=4.5 cm , prove that the area of △APQ is one-sixteenth of the area of △ABC .

1 Answers

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Given, ABC
is a triangle and PQ
is a straight line meeting AB
in P
and AC
in Q
. If AP=1 cm
, PB=3 cm
, AQ=1.5 cm
, QC=4.5 cm
, prove that the area of △APQ
is one-sixteenth of the area of △ABC
.