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Grade: 10

                        

for which value of k will the pair of equations kx+ 3y= k- 3 and 12x+ ky = k have no solution?

2 years ago

Answers : (1)

Arun
24742 Points
							

we have 

kx + 3y - k-3 = 0
12x + ky - k = 0
For given equations to have no solution
a1/a2 = b1/b2 is not equal to c1/c2
k/12 = 3/k
k^2 = 36
k = 6 or k = -6
On putting value of k in the given equation
we get a1/a2 = b1/b2 is not equal to c1/c2
hence the given equation will have no solution both for k=6 & k = -6
2 years ago
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