 ×     #### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
Find two consecutive positive integers, sum of whose squares is 365.
Find two consecutive positive integers, sum of whose squares is 365.

```
3 months ago Anand Kumar Pandey
3071 Points
```							Dear StudentLet us say,the two consecutive positive integers be x and x + 1.Therefore, as per the given questions, x^2 + (x + 1)^2 = 365⇒ x^2 + x^2 + 1 + 2x = 365⇒ 2x^2 + 2x - 364 = 0⇒ x^2 + x - 182 = 0⇒ x^2 + 14x - 13x - 182 = 0⇒ x(x + 14) -13(x + 14) = 0⇒ (x + 14)(x - 13) = 0Thus, either, x + 14 = 0 or x - 13 = 0,⇒ x = - 14 or x = 13since, the integers are positive, so x can be 13,x + 1 = 13 + 1 = 14Therefore, two consecutive positive integers will be 13 and 14Thanks
```
3 months ago
Think You Can Provide A Better Answer ?

## Other Related Questions on 10 grade maths

View all Questions »  ### Course Features

• 728 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions