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. Find the values of k for each of the following quadratic equations, so that they have two equal roots. kx(x - 2) + 6 = 0

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one month ago Anand Kumar Pandey
1572 Points
```							Dear Studentkx(x- 2) + 6 = 0orkx^2- 2kx+ 6 = 0On Comparing the given equation withax^2+bx+c= 0,a=k,b= - 2kandc= 6We know, Discriminant =b^2- 4ac= ( - 2k)^2- 4 (k) (6)= 4k^2- 24kFor equal roots, we know,b^2-4ac=04k^2-24k=04k(k- 6) = 0Either 4k= 0 ork= 6 = 0k= 0 ork= 6However, ifk= 0,then the equation will not have the terms 'x^2' and 'x'.Therefore, if this equation has two equal roots,kshould be 6 only.Thanks
```
one month ago
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