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find the sum of first 99 natural no.s.(arithmetic progression)

vanitha , 7 Years ago
Grade 10
anser 1 Answers
Abu Azbar

Last Activity: 7 Years ago

n=99Therefore : S = n/2(2a+(n-1)d) = 99/2(2*1+(91-1)1) = 99/2 *92 = 99*46 = 4554Therefore the sum of first 99 natural numbers is 4554

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