Find the roots of the following quadratic equations by factorisation: 2x^2 – x +1/8 = 0

Question

Harshit Singh · Answer

Dear Student 2x^2 &ndash; x +1/8 = 0 Taking LHS, =1/8 (16x^2 - 8x + 1) = 1/8 (16x^2 - 4x -4x + 1) = 1/8 (4x(4x - 1) -1(4x - 1)) = 1/8 (4x - 1)^2 The roots of this equation, 2x^2 &ndash; x + 1/8 = 0, are the values of x for which (4x - 1)^2= 0 Therefore, (4x - 1) = 0 or (4x - 1) = 0 &rArr; x = 1/4 or x = 1/4 Thanks

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Find the roots of the following quadratic equations by factorisation: 2x^2 – x +1/8 = 0

Find the roots of the following quadratic equations by factorisation:
2x^2 – x +1/8 = 0

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