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```
. Find the nature of the roots of the following quadratic equations. If the real roots exist, find them; 2x^2 - 6x + 3 = 0
. Find the nature of the roots of the following quadratic equations. If the real roots exist, find them; 2x^2 - 6x + 3 = 0

```
3 months ago Anand Kumar Pandey
3029 Points
```							Dear Student2x^2- 6x+ 3 = 0Comparing the equation withax^2+bx+c= 0, we geta= 2,b= -6,c= 3As we know, Discriminant =b^2- 4ac= (-6)^2- 4 (2) (3)= 36 - 24 = 12b^2-4ac>0,Therefore, there are distinct real roots exist for this equation,2x^2- 6x+ 3 = 0.x = (-(-6) ±√(-6^2-4(2)(3)) )/ 2(2)= (6±2√3 )/4= (3±√3)/2Therefore the roots for the given equation are(3+√3)/2 and (3-√3)/2Thanks
```
3 months ago
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