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Grade: 10

                        

Find the equation to the straight line which passes through the point 5,6 and has intercept on the axis equal in magnitude and both sides are positive

one year ago

Answers : (2)

Aditya Gupta
2065 Points
							
hello samaira, the equation would be
y – 6= m(x – 5), where m is the slope.
note that its intercepts are (5 – 6/m, 0) and (0, 6 – 5m)
given 5 – 6/m= 6 – 5m
or m= – 1, 6/5.
when m= 6/5, the intercepts are 0. but they should be positive. so m= – 1
hence eqn is 
x + y= 11
kindly approve :)
one year ago
Vikas TU
12285 Points
							
 
Dear student 
 
if intercept are equal and opposite in sign then its slope whould be – 1
 
hence equation is x/ a – y/a = 1
 
5/a – 6/a = 1
 
hence a = – 1
 
hence equation is-
 
- x + y = 1
one year ago
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