Grade 1010 grade maths
Find hcf of 65 and 117 and express in the form 65m+ 117n.
1 Answer
Utkarsh Sharma
65=5×13117=3×3×13So we see 13 is the common factor 13 is the HCFNow let n be equal to -1 and m equal to 2So 65m+117n65(2) + 117(-1)=13(HCF)130-117=13(HCF)
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