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cosec 0 - sin 0= a3sec 0 - cos 0=b3Prove thata2b2(a2+b2)=1

cosec 0 - sin 0= a3sec 0 - cos 0=b3Prove thata2b2(a2+b2)=1

Grade:11

1 Answers

Saswat Pani
61 Points
4 years ago
cosec 0 - sin 0= a3sec 0 - cos 0=a3=cosec 0 - sin 0/sec 0 - cos 0a3=cos3o/sin3oa=cos0/sin0b3=cos3o/sin30×sec 0 - cos 0b3=sin3ob=sin0A.T.Qa2b2(a2+b2)=1cos2o/sin2o×sin2o(cos2o/sin2o+sin2o)

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