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10 grade maths

Compare XXII₁₂ (using >,<,=)

  • A. >
  • B. <<
  • C. =
  • D. None

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11 Months agoGrade
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1 Answer

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ApprovedApproved Tutor Answer11 Months ago

To compare the number XXII₁₂, which is in base 12, we first need to convert it to base 10. In base 12, the digits represent powers of 12. Here, XXII₁₂ can be broken down as follows:

Conversion to Base 10

Each digit corresponds to a power of 12:

  • X (10 in base 10) at the 12^1 place: 10 × 12^1 = 120
  • X (10 in base 10) at the 12^0 place: 10 × 12^0 = 10
  • I (1 in base 10) at the 12^-1 place: 1 × 12^-1 = 0.0833

Now, adding these values together:

120 + 10 + 0.0833 = 130.0833

Comparison with Other Values

Now, let's compare XXII₁₂ (which is approximately 130.0833 in base 10) with other values:

  • A. 130
  • B. 131
  • C. 130.0833
  • D. None

Results of the Comparison

Based on the conversion:

  • XXII₁₂ > A (130) because 130.0833 is greater than 130.
  • XXII₁₂ < B (131) because 130.0833 is less than 131.
  • XXII₁₂ = C (130.0833) because they are equal.
  • XXII₁₂ is not None.

In summary, the comparisons yield:

  • XXII₁₂ > A
  • XXII₁₂ < B
  • XXII₁₂ = C
  • XXII₁₂ is not None