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Can you help me with this exercise?cota-tana-2tan2a=4cot4a

pinavo , 7 Years ago
Grade 10
anser 3 Answers
yash lohar

Last Activity: 7 Years ago

To solve this problem simply you should use the formula of cot(a+b)=1/tan(a+b) So use the formula of cot(a+b) to expand cot(2a+2a) and then separate ly divide the numerator by the denominator tan2a and then again to eliminate cot2a so formed use the relation cot(a+a) and follow the same method as done above

sachin

Last Activity: 7 Years ago

To solve this problem simply you should use the formula of cot(a+b)=1/tan(a+b) So use the formula of cot(a+b) to expand cot(2a+2a) and then separate ly divide the numerator by the denominator tan2a and then again to eliminate cot2a so formed use the relation cot(a+a) and follow the same method as done above,

sachin

Last Activity: 7 Years ago

To solve this problem simply you should use the formula of cot(a+b)=1/tan(a+b) So use the formula of cot(a+b) to expand cot(2a+2a) and then separate ly divide the numerator by the denominator tan2a and then again to eliminate cot2a so formed use the relation cot(a+a) and follow the same method as done above,,,,

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