We are given a spherical shell of lead with an external diameter of 18 cm. The shell is melted and recast into a right circular cylinder with a height of 8 cm and a diameter of 12 cm. We need to determine the internal diameter of the shell.
Step 1: Volume of the right circular cylinder
First, we calculate the volume of the cylinder using the formula:
Volume of a cylinder = πr²h
Where:
r = radius of the cylinder
h = height of the cylinder
The diameter of the cylinder is 12 cm, so the radius is:
r = 12 / 2 = 6 cm
The height of the cylinder is given as 8 cm. Thus, the volume of the cylinder is:
Volume of cylinder = π × (6)² × 8 = π × 36 × 8 = 288π cubic centimeters
Step 2: Volume of the spherical shell
The volume of a spherical shell is the difference between the volumes of two spheres: one with the outer radius and one with the inner radius.
The formula for the volume of a sphere is:
Volume of sphere = (4/3)πr³
Let:
R = outer radius of the spherical shell
r = inner radius of the spherical shell
The external diameter of the shell is 18 cm, so the outer radius is:
R = 18 / 2 = 9 cm
The volume of the shell is:
Volume of shell = (4/3)π(R³ - r³)
Substituting the value of R:
Volume of shell = (4/3)π[(9)³ - r³] = (4/3)π[729 - r³]
Step 3: Equating the volumes
Since the lead is melted and recast, the volume of the shell must be equal to the volume of the cylinder:
(4/3)π[729 - r³] = 288π
Canceling π from both sides:
(4/3)[729 - r³] = 288
Multiplying both sides by 3 to eliminate the fraction:
4[729 - r³] = 864
Dividing both sides by 4:
729 - r³ = 216
Now, solving for r³:
r³ = 729 - 216 r³ = 513
Taking the cube root of both sides:
r = ∛513 ≈ 8.04 cm
Step 4: Internal diameter of the shell
The internal diameter of the shell is twice the internal radius:
Internal diameter = 2r = 2 × 8.04 ≈ 16.08 cm
Thus, the internal diameter of the shell is approximately 16.08 cm.