A rhombus of side 20cm each. Find the length of each diagonal.

Hello student,
Please find the answer to your question below
IfABCDis a rhombus with side lengthxthen, by the parallelogram law, and because we know each side has equal length, we know that4x²=|AC|²+|BD|² where|AC|is the length of the diagonal fromAtoCand similarly for|BD|.
As every side is equal it becomes a square
SoIn the case of a square, we get|AC|=|BD|and so2x²=|AC|²⇒|AC|=2√⋅x.
So length of diagonal AC=BD=2=4cm

• What is the parallelogram law ?
• How does it become a square. As the figure given is a rhombus.
• Lastly , I think that for a square there is more criteria than the equality of sides.

Hello student,
Actually there was some misinterpretation in the above answer.
Please find your answer below
IfABCDis a rhombus with side length 20cm then if we draw diagonals.As the diagonals bisect each other at right angles they form 4 pythagorean triangles.
So if we apply pythagoras theorem to each triangle we get


in triangles AOD,COD,BOC,AOB we get the lengths of OA,OB,OC,OD as 10
So AC=OA+OC=20cm
BD=OB+OD=20cm

Hello student,
Please find my response to your question below
It is not possible to find out the length of diagonals if they are not assumed to be same.
If the lengths of diagonals are different then atleast the length of one diagonal should be given.