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10 grade maths> a quadrilateral ABCD circumscribing a cir...

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a quadrilateral ABCD circumscribing a circle of radius 10 cm with sides AB=x cm;BC=38cm;CD=27cm;angle 'A'=90.find x

arun , 9 Years ago

Grade

1 Answers

Ahalya

Last Activity: 9 Years ago

ABCD is a quad with angle a=90 degee.
join BD
you will get a right triangle ABD.
let the centre of the circle be O and the point at which the radius of the circle touches the AB be P.[POINT OF CONTACT]
join OP.
now angle OPA=90.[angle between a radii and a tangent.]
therfore this forms a right triangle.
therfore OA=10 root over 2
therefore AC equals 20root 2.
then you can apply the pythagoras theorem.

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