A car covers its outward journey at 40kmph. It is towed back, over exactly the same distance at 10mph. What is the average speed over the entire journey?

Question

Arun · Answer

Dear student 40 kmph = 40/1.6 mph = 24.85 mph we can apply the formula 2xy/(x+y) for average speed. Now avg speed = 2*24.85*10/34.85 = 14.26 mph

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A car covers its outward journey at 40kmph. It is towed back, over exactly the same distance at 10mph. What is the average speed over the entire journey?

A car covers its outward journey at 40kmph. It is towed back, over exactly the same distance at 10mph. What is the average speed over the entire journey?

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A car covers its outward journey at 40kmph. It is towed back, over exactly the same distance at 10mph. What is the average speed over the entire journey?

A car covers its outward journey at 40kmph. It is towed back, over exactly the same distance at 10mph. What is the average speed over the entire journey?

1 Answers

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Other Related Questions on 10 grade maths

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