A candidate is selected for an interview for three posts. For the first there are 3 candidates, for the second there are 4 and for the third there are 2. What are the chances of his getting at least one post?A)3/4 B)11/12 C)1/4 D)7/8.

To solve this problem, we need to calculate the probability that the candidate will get at least one post.

Step 1: Total number of candidates and posts
For the first post, there are 3 candidates.
For the second post, there are 4 candidates.
For the third post, there are 2 candidates.
Step 2: Probability of not getting any post
The candidate is not selected for a particular post if there are other candidates who get the post. For each post:

Probability of not getting the first post = (Total candidates for the first post - 1) / Total candidates for the first post = (3 - 1) / 3 = 2/3.
Probability of not getting the second post = (Total candidates for the second post - 1) / Total candidates for the second post = (4 - 1) / 4 = 3/4.
Probability of not getting the third post = (Total candidates for the third post - 1) / Total candidates for the third post = (2 - 1) / 2 = 1/2.
Step 3: Probability of not getting any post
The candidate does not get any of the posts if he does not get any of the three posts. The probability of this happening is the product of the probabilities of not getting each post:

Probability of not getting any post = (2/3) * (3/4) * (1/2) = 6 / 24 = 1/4.

Step 4: Probability of getting at least one post
The probability of getting at least one post is the complement of the probability of not getting any post. So:

Probability of getting at least one post = 1 - Probability of not getting any post = 1 - 1/4 = 3/4.

Final Answer:
The chances of the candidate getting at least one post are 3/4.

Thus, the correct answer is A) 3/4.