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8. Find the sum of first 51 terms of an AP whose second and third terms are 14 and 18 respectively.

8. Find the sum of first 51 terms of an AP whose second and third terms are 14 and 18 respectively.

Grade:12th pass

1 Answers

Pawan Prajapati
askIITians Faculty 8740 Points
3 months ago
Given that, Second term, a2 = 14 Third term, a3 = 18 Common difference, d = a3−a2 = 18−14 = 4 a2 = a+d 14 = a+4 a = 10 = First term Sum of n terms; Sn = n/2 [2a + (n – 1)d] S51 = 51/2 [2×10 (51-1) 4] = 51/2 [2+(20)×4] = 51 × 220/2 = 51 × 110 = 5610

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