8. Find the sum of first 51 terms of an AP whose second and third terms are 14 and 18 respectively.

Question

Pawan Prajapati · Answer

Given that, Second term, a2 = 14 Third term, a3 = 18 Common difference, d = a3−a2 = 18−14 = 4 a2 = a+d 14 = a+4 a = 10 = First term Sum of n terms; Sn = n/2 [2a + (n – 1)d] S51 = 51/2 [2×10 (51-1) 4] = 51/2 [2+(20)×4] = 51 × 220/2 = 51 × 110 = 5610

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8. Find the sum of first 51 terms of an AP whose second and third terms are 14 and 18 respectively.

8. Find the sum of first 51 terms of an AP whose second and third terms are 14 and 18 respectively.

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8. Find the sum of first 51 terms of an AP whose second and third terms are 14 and 18 respectively.

8. Find the sum of first 51 terms of an AP whose second and third terms are 14 and 18 respectively.

1 Answers

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