Grade 12th pass10 grade maths
7. Express sin 67° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°.
7. Express sin 67° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°.
1 Answer
Pawan Prajapati
Given:
sin 67° + cos 75°
In term of sin as cos function and cos as sin function, it can be written as follows
sin 67° = sin (90° – 23°)
cos 75° = cos (90° – 15°)
So, sin 67° + cos 75° = sin (90° – 23°) + cos (90° – 15°)
Now, simplify the above equation
= cos 23° + sin 15°
Therefore, sin 67° + cos 75° is also expressed as cos 23° + sin 15°
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