Grade 12th pass10 grade maths
5/(x-1) + 1/(y-2) = 2
6/(x-1) – 3/(y-2) = 1
5/(x-1) + 1/(y-2) = 2
6/(x-1) – 3/(y-2) = 1
1 Answer
Pawan Prajapati
Solution:
Substituting 1/(x-1) = m and 1/(y-2) = n in the given equations, we get,
5m + n = 2 …………………………(i)
6m – 3n = 1 ……………………….(ii)
Multiplying equation (i) by 3, we get
15m + 3n = 6 …………………….(iii)
Adding (ii) and (iii) we get
21m = 7
m = 1/3
Putting this value in equation (i), we get
5×1/3 + n = 2
n = 2- 5/3 = 1/3
m = 1/ (x-1)
⇒ 1/3 = 1/(x-1)
⇒ x = 4
n = 1/(y-2)
⇒ 1/3 = 1/(y-2)
⇒ y = 5
Hence, x = 4 and y = 5
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