 Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        52009+132009÷8 Find the remainder Please tell the process `
one year ago

```							Here, we have 5^2009 + 13^2009We know that a^n + b^n is always divisible by (a+b) when n is odd.2009 is an odd number.So, 5^2009 + 13^2009 is divisible by (5+13) i.e 18.Hence, the remainder is 0.
```
one year ago
```							Actually 5^2009= 5*25^1004 Note that 25=8*3+1Since remainder of 25^n when divided by 8 is 1, so remainder when 5^2009 divided by 8 is 5Now 13^2009=13*169^1004But 169= 8*21+1So remainder when 13^2009 is divided by 8 is 13*1 or 13-8= 5So net remainder is 5+5=10 or 10-8 =2
```
one year ago
Think You Can Provide A Better Answer ?

## Other Related Questions on 10 grade maths

View all Questions »  ### Course Features

• 728 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions